Is “search in gmaps, copy coordinates, paste into Organic Maps” not a viable solution?

I have no idea about that specific app, but wouldn’t (almost) any OSM app have this functionality? E.g. in OsmAnd you can search for the address, open that point’s description, tap on the coordinates and then copy the openstreetmap.org link from the coordinate menu.

Physical media is the only media you really own.

Hard disagree. You can own any file encoded with an open standard. And it’s easier to index, search, manipulate, back up, etc. It feels more like owning than having the data on a micrometer-thick metal layer sandwiched in a fragile plastic disc that can easily scratch or discrot. There is a reason people have been ripping CDs since PC CD drivers became a thing.

Nah, that shit will probably outlive all of us. As the last humans are struggling to survive in the hot hell they used to call earth, someone somewhere will be making a device with USB A <-> Micro B cable included in the box.

Unless digital artists are replaced with AI entirely, I don’t see that happening. iPads (unfortunately) are kind of the golden standard there. If anything I expect drawing tablets without screens to disappear.

If burned properly they hold storage for a very long time without data loss

They also need very particular storage conditions (temperature and humidity in particular), otherwise they will discrot. But yeah they are likely to store data for longer than solid-state media at least.

Honestly I don’t think that’s tru. There were very few kids who truly tinkered with their computers in the old days too - first because not many kids had computers in the first place, and then because computers started being useful without any tinkering. There are still a lot of youths (12-16) today who are flashing LineageOS on their phone or installing Linux on their Chromebook, or whatever. I know because they keep flooding the NixOS Telegram chat that I’m managing - and I try to welcome them with open arms!

smartphones are a black box.

Many Android phones still have a bit of that tinkering ability to them (you kinda have access to the file system, and you can root them/flash custom android distros), but it’s quickly diminishing because (1) OEMs are locking the bootloaders, (2) it’s getting harder and harder to get hardware working without proprietary OEM hacks, (3) bank apps and other proprietary garbage that’s becoming a necessity in modern times refuses to run on an unlocked phone.

I just hope that something like GNU Taler (which keeps buyers’ privacy and forces sellers to report their earnings properly) becomes the norm, as opposed to the proprietary plastic card transactions we have now. I myself am guilty of switching to that system because cash is just insanely inconvenient, but I also recognize it’s pretty bad.

Randall hasn’t bothered to name any of them so the community has given them unofficial nicknames.

Megan is actually named in multiple comics though, so is Danish (Black Hat’s girlfrenemy) (actually that was picked semi-arbitrarily by the community). Cueballs also have different names occasionally but they’re all drawn the same.

And actually I do believe that certain non-named characters are the same comic-to-comic. Black hat and Beret guy almost certainly are.

Yes, as I’ve said, this is just me getting old rather than any issue with the joke format :)

Man, I’m getting old. I don’t understand why all jokes have to be fake twitter screenshots now.

Hehe, in the process of updating :)

CC0 (public domain). You’re free to use it as you like.

Here’s the uncropped image for your convenience too: https://nextcloud.balsoft.ru/s/Zsjii2PfP5ZWFdP?dir=%2F&openfile=true

Eh, this is sure to result in a lot of deaths and destruction, since subway trains don’t have any way to strap you in, and are unlikely to handle the accelerations required to stay on rollercoaster tracks. Also remember that one of his first appearances is https://xkcd.com/72 which seems like child’s play in comparison - he’s sure grown over the years

Yep, although I think StreetComplete does at least ask “how many levels in a building”, which allows for pretty good approximations most of the time

Install StreetComplete, open it, boom, a lot of easy things to do that will help some people out (especially with regards to opening hours, accessibility, addresses and such).

Once you want to do more advanced edits, install Every Door. It’s not as obvious what to do there, but it still highlights issues that need to be fixed and is relatively easy to operate; however, you will need to start looking at OpenStreetMap wiki to take full advantage of it.

Then you can move to more advanced editors, such as Vespucci on your phone (wouldn’t recommend doing everything from there), ID editor in your browser or JOSM as a proper app on your computer.

Actually, recently I learned that setting the tree species (or at least genus) can be very useful to some people: https://lemmy.ml/post/31772921

There’s no such thing as “fully mapped out”. Just open StreetComplete. If there are no tasks left, go ahead and map all the individual trees, or benches, or yield/stop signs, or all the buildings so that they appear good-looking on a 3d render.

While 3D geometry is more difficult for me than 2D, I could almost immediately tell that the answer is no, there are infinitely many points H that satisfy this. The reason it’s unintuitive is that our intuition about what “perpendicular” means comes from 2D and poorly translates to 3D.

The most intuitive explanation I can muster is this: imagine all possible planes that pass through both A and P. It should be obvious that there are infinitely many of them (I visualize it as a plane “rotating” around the AP axis). Each of these planes intersects the given plane since it passes through A. Think of the intersection line. It never passes through P (unless P is on the plane), so it is always possible to draw a perpendicular line from P to that intersection line. With one exception (when the perpendicular line falls on the A point), the point where the perpendicular falls satisfies the conditions for H. (I think all such points actually form a circle with AP’ as the diameter, where P’ is the parallel projection of P to the given plane, but I’m not 100% sure)